Hi all, I can't seem to use fopen to open a file using a variable that stores the name and path of the file. For example, the variable [pathvariable] stores /imper/codec/data.txt. I am doing fid = fopen([pathvariable],'r') but it is not working.
  • fprintf (fileID,formatSpec,A1,...,An) applies the formatSpec to all elements of arrays A1,...An in column order, and writes the data to a text file. fprintf uses the encoding scheme specified in the call to fopen.

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    Dear Sirs:My name is Juan Crespo and I write you from Spain. I answer if you could help me with a Labview problem. This is the problem.I want to write a DLL for being used in labview, and i want to use matlab for write this DLL.

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    2006-06-20 matlab 中如何打开文件; 2018-04-29 MATLAB中fopen要打开的文件与fopen所在的. m... 2016-08-24 一篇纯中文的txt文档,怎样用matlab读取打开,是用fo... 2015-06-10 matlab如何在mac上用fopen打开一个txt文件? 2014-01-22 fopen可以打开哪些位置的文件; 2013-05-28 matlab读取任意路径下 ...

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    2006-06-20 matlab 中如何打开文件; 2018-04-29 MATLAB中fopen要打开的文件与fopen所在的. m... 2016-08-24 一篇纯中文的txt文档,怎样用matlab读取打开,是用fo... 2015-06-10 matlab如何在mac上用fopen打开一个txt文件? 2014-01-22 fopen可以打开哪些位置的文件; 2013-05-28 matlab读取任意路径下 ...

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